File System
medium · tree, paths
Brief-reported interview attribution (unverified): LeetCode 588 is the design-round version of this question
How to approach an LLD roundImplement a simple in-memory file system. Directories contain
sub-directories and files. mkdir creates nested directories as needed.
add_content(path, content) creates the file if it does not exist and appends to
it if it does. ls(path) lists a directory's children (directories and files,
sorted together) or, for a file path, returns just that file's name.
read_content(path) returns a file's content, or None if the path is not a
file.
class FileSystem:
def __init__(self):
def mkdir(self, path):
# creates all missing directories along the path ("/" already exists)
def add_content(self, path, content):
# -> True if the file was created/appended, False if a parent directory is missing
def ls(self, path):
# -> sorted list of names; [] for a path that does not exist
def read_content(self, path):
# -> content (str), or None if the path is not a file
Rules. Paths are absolute (/a/b/c). ls("/") lists the root. add_content
does not create missing parent directories — it returns False instead.
read_content on a directory returns None.
Tests use explicit inputs and injected clocks/callbacks. No network, real threads or application-server execution is involved.
Public demo
# Public demo: run after implementing the class API above.
f = FileSystem()
f.mkdir('/a/b')
f.mkdir('/a/c')
f.add_content('/a/b/f.txt', 'hello')
print(f.read_content('/a/b/f.txt'))Starter code
class FileSystem:
def __init__(self):
"""Initialize the state described in the problem."""
pass
def mkdir(self, path):
"""creates all missing directories along the path ("/" already exists)"""
pass
def add_content(self, path, content):
"""-> True if the file was created/appended, False if a parent directory is missing"""
pass
def ls(self, path):
"""-> sorted list of names; [] for a path that does not exist"""
pass
def read_content(self, path):
"""-> content (str), or None if the path is not a file"""
pass
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